C++ program to illustrate pointer arithmetic

Here is a C++ program to illustrate pointer arithmetic


 SOURCE CODE OUTPUT

#include<iostream>
using namespace std;
int main()
{
    int x=0,*p,*q,y;
    p=&x;
    q=p;
    cout<<"Address in pointer :"<<int(p)<<endl;
    ++p;
    cout<<"After incrementing : "<<int(p)<<endl;
    y=p-q;
    cout<<"Difference  "<<int(p)<<"-"<<int(q)<<" = "<<y<<endl;
    ++p;
    cout<<"Again incrementing :"<<int(p)<<endl;
    y=p-q;
    cout<<"Now the Difference   "<<int(p)<<"-"<<int(q)<<" = "<<y<<endl;
    return 0;
}

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