C++ program to print integers from 1 to n leaving values that are divisible by x

Here is a C++ program to print integers from 1 to n leaving values that are divisible by x


 SOURCE CODE OUTPUT

#include<iostream>
using namespace std;
int main()
{
    long sum=0,n,y=1,x;
    cout<<"Enter the value of x ";
    cin>>x;
    cout<<"Enter the value of n ";
    cin>>n;
    for(int i=1;i<=n;i++)
    {
        if(i%x!=0)
        {
            cout<<i<<" ";
           sum+=i;
        }
    }
    cout<<endl<<"Sum "<<sum<<endl;
    return 0;
}

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