Here is a C++ program to print the abundant numbers from 1 to n
SOURCE CODE OUTPUT
#include<iostream>
using namespace std;
int main()
{
long sum=0,n;
cout<<"Enter the value of n ";
cin>>n;
for(int y=1;y<=n;y++)
{
for(int i=1;i<y;i++)
{
if(y%i==0)
sum+=i;
}
if(sum>y)
cout<<y<<" ";
sum=0;
}
return 0;
}
using namespace std;
int main()
{
long sum=0,n;
cout<<"Enter the value of n ";
cin>>n;
for(int y=1;y<=n;y++)
{
for(int i=1;i<y;i++)
{
if(y%i==0)
sum+=i;
}
if(sum>y)
cout<<y<<" ";
sum=0;
}
return 0;
}
Any questions regarding to program please write in comments.
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